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Author Topic: can't find dual gang 20K W pot  (Read 2519 times)
peter
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« on: May 26, 2009, 10:21:13 PM »

Hi there,

I'm looking for a dual gang 20K W pot for my project but just can't find one. Anybody knows if they actually exist?? I searched my ass off, but without any result.
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Gordonjcp
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« Reply #1 on: May 26, 2009, 10:47:34 PM »

http://www.bargainshack.co.uk/product/Standard-Potentiometers-Pot-Lin-22k.html
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peter
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« Reply #2 on: May 26, 2009, 11:01:19 PM »

You're saying I could just use a lin dual gang pot? What about the W (curve, or what it means)?
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peter
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« Reply #3 on: May 26, 2009, 11:32:57 PM »

haha. I'm new to this and and still struggling with things. I'm trying to build me a stereo Tube Screamer and according to the schematic there's a 20K W pot in it.

Thanks for your reaction by the way!
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crustypaul
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« Reply #4 on: May 27, 2009, 12:25:48 AM »

W doesn't mean anything in terms of any kind of curve i know of.

Wheres the schematic
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Gordonjcp
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« Reply #5 on: May 27, 2009, 10:06:21 AM »

No, I've never come across a W curve either.  If you use the wrong taper, the control will be a bit "all up one end".  You may find that for the distortion control on an effect you need a reverse-log taper pot, which is pretty much impossible to get.  There are a couple of clever tricks you can do with resistors though...
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peter
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« Reply #6 on: May 27, 2009, 10:57:34 AM »

great that you're helping me out with this! I really don't know where th W stands for. The curve thing is what i found looking on the net.

Here's the schematic. I got it from NEWTONE (http://www.newtone-online.nl/downloads/NewtoneScreamer.pdf), it's a dutch website. But i put the schematic here:


* schematic Tube Screamer.jpg (50.15 KB, 1134x567 - viewed 104 times.)
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peter
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« Reply #7 on: May 27, 2009, 10:58:48 AM »

...itīs the TONE pot
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peter
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« Reply #8 on: May 27, 2009, 11:01:38 AM »

Here's the Tonepad Tube Screamer http://www.tonepad.com/getFile.asp?id=81. I noticed that this one is using a 20K lin pot indeed.
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Gordonjcp
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« Reply #9 on: May 27, 2009, 01:08:15 PM »

Looks very much like the tone pot is supposed to be linear.  I don't see why you need a dual gang one though...
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peter
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« Reply #10 on: May 27, 2009, 01:22:50 PM »

I think I got the solution to my problem!!

I'm trying to make two Tube Screamers so i can run them in stereo to run my sampler through them. And in order to control both at the same time I'll need dual pots, else I'll be turning to many knobs..
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LoFi-Ninja
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« Reply #11 on: May 27, 2009, 02:01:33 PM »

If your doing this in sterio keep in mind that you should get the best quality parts you can afford !

This meaning 1% resistors and capacitors and perhaps pairing your transistors aswell as maybe heatsinking your IC's.. Heatsinking might be overkill thou..

What I'm trying to say is that if you don't do this one channel might sound way different from the other in you production..
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Gordonjcp
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« Reply #12 on: May 27, 2009, 03:45:15 PM »

You shouldn't ever need to heatsink the opamps in a fuzzbox.  They're not developing any real power.

I'd be surprised if you could tell much difference between the left and right channels of a stereo fuzzbox, although it may be worth matching the four clipper diodes and the input transistors.  Most modern components are far more closely matched than the ones used to build these old stompboxes *anyway* though...
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« Reply #13 on: May 27, 2009, 05:32:40 PM »

I got some AC188 transistors i'm using in some fuzz face clones, some of which have built in heatsinks, and they do sound kind of 'tighter' than the ones without heatsinks.

Although that could just be down to the wild variations in tolerances between individual transistors.
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LoFi-Ninja
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« Reply #14 on: May 27, 2009, 05:52:14 PM »

You shouldn't ever need to heatsink the opamps in a fuzzbox.  They're not developing any real power.

That's why I said that would be overkill  Tongue

I'd be surprised if you could tell much difference between the left and right channels of a stereo fuzzbox

If your using germanium transistors you will sertanly hear it unless you match them..

Although that could just be down to the wild variations in tolerances between individual transistors.

Well they are germanium aren't they  Grin
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